What is the slope-intercept form of the line passing through # (-4, 1) # and #(-3, 5) #?

Question

What is the slope-intercept form of the line passing through #  (-4, 1) # and #(-3, 5)  #?

Avery Alexander · Accepted Answer

#y=4x+17# #"the equation of a line in "color(blue)"slope-intercept form"# is. #•color(white)(x)y=mx+b# #"where m is the slope and b the y-intercept"# #"to calculate m use the "color(blue)"gradient formula"# #•color(white)(x)m=(y_2-y_1)/(x_2-x_1)# #"let "(x_1,y_1)=(-4,1)" and "(x_2,y_2)=(-3,5)# #rArrm=(5-1)/(-3-(-4))=4/1=4# #rArry=4x+blarrcolor(blue)"is the partial equation"# #"to find b substitute either of the 2 given points into"# #"the partial equation"# #"using "(-3,5)" then"# #5=-12+brArrb=5+12=17# #rArry=4x+17larrcolor(red)"in slope-intercept form"#

Abigail Allen · Answer

undefined To find the slope-intercept form of the line passing through the points (-4, 1) and (-3, 5), first find the slope using the formula: slope = (change in y) / (change in x). Then, use the point-slope form of a linear equation, y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope, to find the equation of the line. Finally, simplify the equation to slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.