What is the slope intercept form of the line passing through #(1,-6) # with a slope of #-6 #?

Substituting this now gives:

The slope-intercept form of the line passing through the point (1, -6) with a slope of -6 is y = -6x - 12.

The slope-intercept form of a linear equation is given by y = mx + b, where m is the slope of the line and b is the y-intercept.

Given that the line passes through the point (1, -6) and has a slope of -6, we can substitute these values into the slope-intercept form equation.

So, m = -6 and the point (1, -6) lies on the line. We can substitute these values into the equation to find the y-intercept, b.

-6 = (-6)(1) + b -6 = -6 + b b = -6 - (-6) b = -6 + 6 b = 0

Now that we have found the value of b, we can write the equation of the line in slope-intercept form:

y = -6x + 0

Simplifying, we get:

y = -6x

So, the slope-intercept form of the line passing through the point (1, -6) with a slope of -6 is y = -6x.