What is the simplest radical form for #sqrt(145)#?

Answer 1

#sqrt145#

There is no simple form for this.

Let's try using the factors of #145#
#sqrt145=sqrt145*sqrt1#
#sqrt145=sqrt29*sqrt5#
This cannot be broken into any simpler forms so there is no simple from for #sqrt145#
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Answer 2

#sqrt(145)#

The prime factorisation of #145# is:
#145 = 5*29#
Since this has no square factors, there is no simpler radical form than #sqrt(145)#.
Note however that #145 = 12^2+1# is of the form #n^2+1#

As a result, its square root has a very simple form as a continued fraction:

#sqrt(145) = [12;bar(24)] = 12+1/(24+1/(24+1/(24+1/(24+1/(24+...)))))#
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Answer 3

The simplest radical form for ( \sqrt{145} ) is ( \sqrt{145} ).

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Answer 4

The simplest radical form for ( \sqrt{145} ) is ( \sqrt{145} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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