# What is the second derivative of #y = lnx^2#?

For the first derivative, use the chain rule.

By the quotient rule:

Hopefully this helps!

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To find the second derivative of ( y = \ln(x^2) ), first find the first derivative using the chain rule:

[ \frac{dy}{dx} = \frac{1}{x^2} \cdot 2x = \frac{2}{x} ]

Now, differentiate the first derivative with respect to ( x ) to find the second derivative:

[ \frac{d^2y}{dx^2} = -\frac{2}{x^2} ]

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