# What is the second derivative of #x^2 + (16/x)#?

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To find the second derivative of the function ( f(x) = x^2 + \frac{16}{x} ), we first find the first derivative and then differentiate it again.

( f'(x) = 2x - 16x^{-2} )

Now, differentiate ( f'(x) ) with respect to ( x ) to find the second derivative:

( f''(x) = 2 + 32x^{-3} )

So, the second derivative of ( x^2 + \frac{16}{x} ) is ( 2 + 32x^{-3} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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