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What is the resulting molarity of solution when 2g of NaOH is dissolved in 500 ml of water? (molar mass of NaOH=40.)?

Answer 1

Mateo Aguilar

#"Molarity"# #=# #0.10*mol*L^-1# with respect to #NaOH#.

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

#"Molarity"# #=# #(2*g)/(40.0*g*mol^-1)xx1/(500*mLxx10^-3*L*mL^-1)#

#=# #??mol*L^-1#.

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Answer 2

Natalie Anton

To find the molarity of the solution, first calculate the number of moles of NaOH: Number of moles = mass of NaOH / molar mass of NaOH

mass of NaOH = 2g molar mass of NaOH = 40 g/mol

Number of moles = 2g / 40 g/mol = 0.05 moles

Then, use the formula for molarity: Molarity (M) = Number of moles / Volume of solution (in liters)

Volume of solution = 500 ml = 0.5 L

Molarity (M) = 0.05 moles / 0.5 L = 0.1 M

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.