# What is the removable and nonremovable discontinuities in the equation #(x-2)/(x^2 + x - 6)#?

it is still discontinuous at -3, but it is continuous at 2

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The removable discontinuity occurs when the numerator of the rational function is equal to zero, resulting in a hole in the graph. In the given equation, the removable discontinuity occurs at x = 2.

The nonremovable discontinuity, also known as a vertical asymptote, occurs when the denominator of the rational function is equal to zero. In the given equation, the nonremovable discontinuity occurs at x = -3 and x = 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you evaluate the limit #2t# as t approaches #1#?
- How do you evaluate # ( x^2+2) /( sqrt (9x^4 +1))# as x approaches infinity?
- How do you find the limit of #(2x-1)/(abs(2x^3 - x^2))# as x is approaching 0.5 from the negative side?
- What is the limit of #sin[(pix) /(2-3x)]# as x approaches infinity?
- How do you evaluate #[ (ln x) / (csc x) ]# as x approaches 0+?

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