# What is the range of the graph of #y = 5(x – 2)^2 + 7#?

Where:

If:

For instance:

Thus, in interval notation, the function's range is:

plot{y=5(x-2)^2+7 [-10, 10, -5, 41.6]}

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The given quadratic function is in vertex form (y = a(x - h)^2 + k), where ((h, k)) is the vertex of the parabola. The range of the graph is determined by the value of (a).

For (y = 5(x - 2)^2 + 7), the minimum value occurs at the vertex ((2, 7)), and since (a = 5) is positive, the parabola opens upwards. Therefore, the range is (y \geq 7).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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