What is the range of a function like #f(x) = sqrt (x-5)#?

Answer 1

The argument of the square rood has to be not-negative, so:

#x>=5# or #[5,+oo)#.
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Answer 2

The range of the function ( f(x) = \sqrt{x-5} ) is all real numbers greater than or equal to zero. In other words, the range is the set of all non-negative real numbers. This is because the square root function outputs non-negative values only, and as ( x ) increases from ( 5 ), ( \sqrt{x-5} ) also increases, starting from ( 0 ). Therefore, the range of ( f(x) ) is ([0, \infty)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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