What is the product of adding an amine (#RNH_2#) to #HCl#? What about #ArOH+NaHCO_3+NaOH#?

Question

Madison Anderson · Accepted Answer

Pl see below

#RNH_2+HCl=RNH_3^+Cl^-#
The amine is basic in nature due its loan pair on N atom . So it donates its loan pair to the electron deficit #H^+# formed by dissociation of HCl as follows
#HCl=H^++Cl^-#

The benzo-phenol is a weak acid (pKa= ~10) and do not react with sodium bicarbonate, which is a weak base itself (pKa(H2CO3)=6.37, 10.3). However, it does react with a strong base like NaOH.as follows

Maya Allen · Answer

undefined Adding an amine (RNH2) to HCl produces an ammonium salt (RNH3^+ Cl^-). ArOH + NaHCO3 + NaOH does not result in a single specific product, but rather a series of reactions. Initially, ArOH (an aromatic alcohol or phenol) reacts with NaHCO3 (sodium bicarbonate) to produce effervescence (bubbling) of CO2 gas and the formation of the corresponding sodium salt (ArO^- Na^+). Subsequently, the addition of NaOH (sodium hydroxide) results in the deprotonation of the sodium salt, yielding the corresponding phenoxide ion (ArO^-) and water (H2O).