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What is the product (in simplest radical form) of the square route of 6 and the square root of 15?

Answer 1

#sqrt(6)*sqrt(15) = 3sqrt(10)#

By radical laws, #sqrt(a) * sqrt(b) = sqrt(ab)#.

Using this law: #sqrt(6)*sqrt(15)# #=sqrt(90)#

#sqrt(90)# has #9#, a perfect square, as one of its factors, so it can be simplified. #sqrt(90)# #=sqrt(9*10)# #=sqrt(9)*sqrt(10)# #=3sqrt(10)#

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Answer 2

Ethan Adkins

The product of the square root of 6 and the square root of 15, in simplest radical form, is the square root of 90.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.