# What is the probability of not tossing three heads with three fair coins?

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The probability of not tossing three heads with three fair coins can be calculated by finding the probability of getting zero, one, or two heads, and then subtracting that from 1.

Probability of getting zero heads: ( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} )

Probability of getting one head: ( \binom{3}{1} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{3}{8} )

Probability of getting two heads: ( \binom{3}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{3}{8} )

Now, add these probabilities together:

( \frac{1}{8} + \frac{3}{8} + \frac{3}{8} = \frac{7}{8} )

Finally, subtract this total probability from 1 to find the probability of not tossing three heads:

( 1 - \frac{7}{8} = \frac{1}{8} )

So, the probability of not tossing three heads with three fair coins is ( \frac{1}{8} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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