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What is the pressure in a 10.0-L cylinder filled with 0.460 mol of nitrogen gas at a temperature of 314 K?

Answer 1

Henry Antrim

Approx. #1*atm#. We use the Ideal Gas equation.........

#P=(nRT)/V=(0.460*cancel(mol)xx(0.0821*cancelL*atm)/(cancelK*cancel(mol))xx314*cancelK)/(10.0*cancelL)#

#=# #??atm#

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Answer 2

Wyatt Adkins

To find the pressure of the nitrogen gas in the cylinder, you can use the ideal gas law equation:

PV = nRT

Where: P = pressure (in atm) V = volume (in liters) n = number of moles R = ideal gas constant (0.0821 L atm / mol K) T = temperature (in Kelvin)

Plug in the given values and solve for pressure (P).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.