What is the potential energy of a 2.5 kg book held 2.0 m above the ground?

Answer 1

#49J# of energy

Formula for potential energy: #P.E=mgh# #m = # mass(#kg#) #g = # gravity(#m#/#s^2#) #h = # height/distance(#m#)
What is given to you? Well the book is held from the ground of a distance #2.0m#, so #h=2.0m#. Next we know that the book weighs #2.5kg#, so #m=2.5kg#.
Now we just put it in the formula: #PE=(2.5kg)xx(9.8m#/#s^2)xx(2.0m)# #PE=49J#
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Answer 2

The potential energy of the book held 2.0 m above the ground can be calculated using the formula for gravitational potential energy:

( PE = mgh )

Where: ( m = 2.5 , kg ) (mass of the book) ( g = 9.8 , m/s^2 ) (acceleration due to gravity) ( h = 2.0 , m ) (height above the ground)

Substituting the values:

( PE = (2.5 , kg) \times (9.8 , m/s^2) \times (2.0 , m) )

( PE = 49 , J )

So, the potential energy of the book held 2.0 m above the ground is 49 joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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