# What is the polar form of #( 36,48 )#?

Polar form of

By signing up, you agree to our Terms of Service and Privacy Policy

To find the polar form of the point ( (36, 48) ), we use the formulas:

[ r = \sqrt{x^2 + y^2} ] [ \theta = \arctan\left(\frac{y}{x}\right) ]

where ( r ) represents the distance from the origin to the point, and ( \theta ) represents the angle between the positive x-axis and the line connecting the origin to the point.

Given ( (x, y) = (36, 48) ), we calculate:

[ r = \sqrt{36^2 + 48^2} = \sqrt{1296 + 2304} = \sqrt{3600} = 60 ]

[ \theta = \arctan\left(\frac{48}{36}\right) = \arctan\left(\frac{4}{3}\right) ]

Using a calculator to find the arctan value, we get ( \theta \approx 53.13^\circ ) (rounded to two decimal places).

Therefore, the polar form of ( (36, 48) ) is ( (60, 53.13^\circ) ).

By signing up, you agree to our Terms of Service and Privacy Policy

- What is the slope of the tangent line of #r=2theta-cos(5theta-(2pi)/3)# at #theta=(-7pi)/4#?
- What is the area enclosed by #r=theta^2-2sintheta # for #theta in [pi/4,pi]#?
- What is the slope of the tangent line of #r=2theta^2-3thetacos(2theta-(pi)/3)# at #theta=(-5pi)/3#?
- What is the equation of the tangent line of #r=cos(theta-pi/4) +sin^2(theta+pi)-theta# at #theta=(-13pi)/4#?
- What is the distance between the following polar coordinates?: # (3,(5pi)/4), (1,(pi)/8) #

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7