# What is the polar form of #( -18,-6 )#?

We're asked to find the polar form of a rectangular coordinate.

We can do so by using the equations

The polar form of this coordinate is thus

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The polar form of the point ((-18, -6)) can be found using the conversion formulas:

[ r = \sqrt{x^2 + y^2} ] [ \theta = \arctan\left(\frac{y}{x}\right) ]

Substituting the given values, we get:

[ r = \sqrt{(-18)^2 + (-6)^2} = \sqrt{324 + 36} = \sqrt{360} = 6\sqrt{10} ] [ \theta = \arctan\left(\frac{-6}{-18}\right) = \arctan\left(\frac{1}{3}\right) ]

Therefore, the polar form of the point ((-18, -6)) is (6\sqrt{10} , \text{cis}(\arctan(1/3))).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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