What is the polar form of #( -13,14 )#?

Answer 1

#(r,theta)~~(19.1,2.3" [radians]")#

#(x,y)=(-13,14)# is a point in Quadrant II So #theta# must be #in [0,pi]#

The radius (distance from the origin) for the point #(x,y)# is #sqrt(x^2+y^2)# In this case #color(white)("XXX")r=sqrt((-13)^2+14^2)~~19.10497...# (using a calculator)

The tangent for this angle #(theta)# is #y/x# In this case #color(white)("XXX")tan(theta)=14/(-13)# which implies #color(white)("XXX")theta=arctan(-14/13)~~2.3191744...# (again using a calculator Note: you might need to adjust for the quadrant if your #arctan# function gives a value in the range #[-pi/2,+pi/2]#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Scarlett Allison

The polar form of (-13, 14) is approximately (19.21, 128.66°).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.