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What is the polar form of #( 13,1 )#?

Answer 1

Isabella Ackerman

#(sqrt(170),tan^-1(1/13))-=(13.0,0.0768^c)#

For a given set of coordinates #(x,y)#, #(x,y)->(rcostheta,rsintheta)#

#r=sqrt(x^2+y^2)# #theta=tan^-1(y/x)#

#r=sqrt(13^2+1^2)=sqrt(169+1)=sqrt(170)=13.0# #theta=tan^-1(1/13)=0.0768^c#

#(13,1)->(sqrt(170),tan^-1(1/13))-=(13.0,0.0768^c)#

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Answer 2

Samantha Adkison

The polar form of the complex number (13, 1) is given by (13 \text{cis}(1)), where "cis" stands for cosine plus the imaginary unit times sine.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.