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What is the polar form of #( 11,-9 )#?

Answer 1

The polar form of the coordinate pair #(11, -9)# is #(sqrt(202), -39.289)#.

The polar form of a coordinate pair #(x, y)# is #(r, theta)#. To find r, we use the formula #r^2 = x^2+y^2#. #r^2 = 11^2 + (-9)^2# #r^2 = 121 + 81# #r^2 = 202# #r = sqrt(202)# #r ~~ 14.21# To find #theta#, we use the formula #y/x = tan(theta)#. #(-9)/11 = tan(theta)# #theta = tan^-1((-9)/11)# #theta ~~ tan^-1(0.818182)# #theta ~~ -39.289407#

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Answer 2

Isabella Ackerman

The polar form of the complex number (11, -9) is approximately (15.81\angle{-39.81^\circ}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.