What is the polar form of #( 0,-2 )#?

Answer 1

#(2, 3pi/2)#

x = r cos #theta# = 0. As both x and y are not 0, r is not 0. So, cos #theta# = 0. #theta=pi/2 or 3pi/2#.

r sin #theta# = #-2#. sin #theta =+-1#. So, r =#=2 or-2#. Both are one and the same point It is a better convention to keep r#>=0#. Answer #(2, 3pi/2) or (-2, pi/2)#

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Answer 2

Emilia Aguilar

The polar form of the point ((0, -2)) is (2\angle \frac{3\pi}{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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