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What is the point-slope form of an equation with the slope 3⁄5 that passes through the point (10, −2)?

Answer 1

Answer: # y + 2 = 2/5(x - 10)#

The general form is: # y - y_0 = m(x - x_0)# where #m# is the gradient and #(x_0, y_0)# is the point through which the line passes

so you do # y - (-2) = 3/5(x - 10)# #=> y + 2 = 3/5(x - 10)#

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Answer 2

Hazel Anglin

The point-slope form of a linear equation is given by:

[y - y_1 = m(x - x_1)]

where ((x_1, y_1)) is a point on the line, and (m) is the slope of the line. Given (m = \frac{3}{5}) and the point ((10, -2)), we substitute (x_1 = 10), (y_1 = -2), and (m = \frac{3}{5}) into the formula:

[y - (-2) = \frac{3}{5}(x - 10)]

Simplifying, we get:

[y + 2 = \frac{3}{5}(x - 10)]

This is the point-slope form of the equation with the given slope and point.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.