What is the point of intersection between the equations #3x+5y=78# and #2x-y=0#?

Answer 1

At the point (6,12), i.e. x=6 and y=12.

Multiply the second equation by 5. One gets #10x - 5y = 0#. Add this to the first equation to get #13x=78#. So, #x=6#. Substituting 6 for x in the second equation yields #12 - y = 0# or, equivalently, #y=12#.
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Answer 2

To find the point of intersection between the equations (3x + 5y = 78) and (2x - y = 0), you can solve the system of equations simultaneously.

First, solve the second equation ((2x - y = 0)) for (y) in terms of (x): [2x - y = 0] [y = 2x]

Then, substitute this expression for (y) into the first equation: [3x + 5(2x) = 78] [3x + 10x = 78] [13x = 78] [x = \frac{78}{13}] [x = 6]

Now that you have found the value of (x), substitute it back into either of the original equations to find the corresponding value of (y). Let's use the second equation ((2x - y = 0)): [2(6) - y = 0] [12 - y = 0] [y = 12]

So, the point of intersection between the equations (3x + 5y = 78) and (2x - y = 0) is ((6, 12)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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