# What is the perimeter of a triangle with vertices of (2,0), (2, -3) and (-2,-3)?

Perimeter of the triangle = 12 units.

Construct a triangle ABC with the given vertices:

Perimeter of the triangle ABC :

To find the magnitudes of the sides AB, BC and AC, use the distance formula:

Distance(D) between the two points:

Distance between two points:

Distance between two points:

Hence, the Perimeter of the triangle ABC

Measure the distances between points on the coordinate plane:

Measure the angle

Verify that the angle is

Hence, triangle

Hope it helps.

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The perimeter is 12.

The best way to start on this question is to plot those points and draw the triangle.

You can immediately see that it is a right triangle.

You can count the intervals between (2,0) and (2,-3).

Then you can count the intervals between (2,-3) and (-2,-3)

Now you can see that it is a 3-4-5 right triangle.

To solve this problem with math instead of counting:

- Find the length of one leg The distance between (2,0) and (2,-3) is 0 - (-3), which is 3

- Find the length of the other leg The distance between (2,-3) and (-2,-3) is 2 - (-2), which is 4.

- A right triangle with legs 3 and 4 must be a 3-4-5 right triangle.

- So the perimeter (the sum of the lengths of all three sides) must be 3 + 4 + 5, which is 12.

Answer: The perimeter is 12.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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