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What is the perimeter of a triangle with corners at #(9 ,2 )#, #(2 ,3 )#, and #(4 ,1 )#?

Answer 1

#sqrt50 +sqrt8 +sqrt26#

We know the distance between two points P(x1,y1) and Q(x2,y2) is given by PQ= #sqrt[(x2 -x1)^2 + (y2 - y1)^2]# First we have to calculate the distance between (9,2)(2,3) ; (2,3)(4,1) and (4,1)(9,2) to get the lengths of the sides of triangles. Hence lengths will be #sqrt[(2-9)^2+(3-2)^2] = sqrt[(-7)^2 + 1^2] = sqrt(49+1) = sqrt50# #sqrt [(4-2)^2 +(1-3)^2] = sqrt[(2)^2 +(-2)^2] = sqrt[4+4]=sqrt8# and # sqrt[(9-4)^2 +(2-1)^2] = sqrt[5^2+1^2] = sqrt26 # Now the perimeter of the triangle is #sqrt50 +sqrt8 +sqrt26#

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Answer 2

Evelyn Arboleda

The perimeter of the triangle with corners at (9, 2), (2, 3), and (4, 1) is approximately 18.24 units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.