What is the percentage composition of #NH_4I#?

Answer 1

Well, the molar mass of ammonium iodide is #144.94*g*mol^-1#...

And so #%I-=(126.9*g*mol^-1)/(144.94*g*mol^-1)xx100%=87.6%#
And #%N-=(14.01*g*mol^-1)/(144.94*g*mol^-1)xx100%=9.67%#
And #%H-=(4xx1.00794*g*mol^-1)/(144.94*g*mol^-1)xx100%=2.80%#

Iodides have some good solubilities in solvents like acetone, but the problem with using them is that their salts are so heavy that you have to add a large mass to get the required equivalency.

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Answer 2

The molar mass of NH4I, which is made up of one nitrogen (N), four hydrogen (H), and one iodine (I) atom, is calculated as follows: N: 14.01 g/mol, H: 1.01 g/mol, and I: 126.90 g/mol. Total molar mass = 14.01 + (4 * 1.01) + 126.90 = 142.94 g/mol. The percentage composition is then determined by multiplying the mass by the percentage of N (mass of N / Total molar mass) * 100%, the percentage of H (mass of H / Total molar mass) * 100%, and the percentage of I (mass of I / Total molar mass) * 100%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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