# What is the percentage composition of #NH_4I#?

Well, the molar mass of ammonium iodide is

Iodides have some good solubilities in solvents like acetone, but the problem with using them is that their salts are so heavy that you have to add a large mass to get the required equivalency.

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The molar mass of NH4I, which is made up of one nitrogen (N), four hydrogen (H), and one iodine (I) atom, is calculated as follows: N: 14.01 g/mol, H: 1.01 g/mol, and I: 126.90 g/mol. Total molar mass = 14.01 + (4 * 1.01) + 126.90 = 142.94 g/mol. The percentage composition is then determined by multiplying the mass by the percentage of N (mass of N / Total molar mass) * 100%, the percentage of H (mass of H / Total molar mass) * 100%, and the percentage of I (mass of I / Total molar mass) * 100%.

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