What is the percent yield if 4.65 g of copper is produced when 1.87 g of aluminum reacts with an excess of copper(II) sulfate?

Answer 1

The % yield when 4.65 g of copper is produced will be 70.4 %.

The equation that balances this would be

#"2Al" + "3CuSO"_4 → "3Cu" + "Al"_2("SO"_4)_3#
1.87 g of Al is #"0.0693 moles Al" × "3 moles of Cu"/"2 moles of Al" = "0.10396 moles of Cu"#.

The theoretical yield is 6.606 g of Cu, which is equivalent to this.

#"Actual"/"Theoretical" × 100 % = "% yield": 4.65/6.606 × 100 % = 70.4 %#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

The percent yield of the reaction is 86.6%.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7