What is the percent of increase from 270cm³ to 750cm³?

Answer 1

#177.77bar7%# not accurate solution.

#177 7/9 %# accurate solution.

Method#-> ("difference")/("original value")xx100#

#=> (750-270)/270xx100 = 177.77bar7%#

The bar over the last 7 means it goes on repeating for ever. '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ There is a trick you can use to deal with repeating decimals You convert them to fractions. Sometimes you need to multiply by a different value: #10^n# as appropriate

Let #x=177.77bar7#

The #10x=1777.77bar7#

So #10x-x ->1777.77bar7# #" "ul(" "177.77bar7)" "larr" subtract"# #" "1600#

So #9x=1600 => x= 1600/9 = 177 7/9 %#

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Answer 2

Eli Assouline

To find the percent increase from 270 cm³ to 750 cm³:

Calculate the difference between the two volumes: ( 750 , \text{cm}^3 - 270 , \text{cm}^3 = 480 , \text{cm}^3 )
Calculate the percent increase: ( \frac{480}{270} \times 100% = \frac{480}{270} \times 100% \approx 177.78% )

Therefore, the percent increase from 270 cm³ to 750 cm³ is approximately 177.78%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.