What is the percent composition of nitrogen for #Sr(NO_3)_2#?

Answer 1

13.237 %

The molecular weight of Sr(NO3)2 is 211.62 gm Atomic weight of Nitrogen is 14.0067 gm Since there is two atoms of Nitrogen in Sr(NO3)2 Therefore total Nitrogen is #14.0067*2# = 28.0134 Since 28.0134 gm Nitrogen is in 211.62 gm Sr(NO3)2 Hence what is for per 100 gm [ percent] of Sr(NO3)2

Thus

#28.0134*100/211.62# = 13.237

The result is 13.237 percent.

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Answer 2

Sr(NO3)2 has a nitrogen content of 25.86 percent.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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