What is the percent composition by weight of #Al# in #Al_2(SO_4)3#?

Answer 1

#%"Composition"="Mass of component"/"Molar mass of compound"# #xx100%#, approx. 16% with respect to aluminum.

#(2xx26.98*g*mol^-1)/(342.15*g*mol^-1)xx100%# #=# #??%#
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Answer 2

In order to determine the percent composition by weight of aluminum (Al) in ( Al_2(SO_4)_3 ), you must first determine the molar masses of the compound as a whole and of the aluminum itself. You can then use the following formula: [ \text{Percent composition of Al} = \frac{\text{Molar mass of Al} \times 2}{\text{Molar mass of } Al_2(SO_4)_3} \times 100% ] Molar mass of Al = 26.98 g/mol Molar mass of ( Al_2(SO_4)_3 ) = (2 * molar mass of Al) + (3 * molar mass of S) + (12 * molar mass of O) Molar mass of ( Al_2(SO_4)_3 ), then plug the values into the formula to determine the percent composition by weight of aluminum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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