What is the percent composition by mass of aspartame #C_14H_18N_2O_5#?

Answer 1

I will solve for percentage composition of #N# in the compound.

Molecular mass of aspartame: #=# #(14xx12.011+18xx1.00794+2xx14.011+5xx15.999)*g*mol^-1#
#=# #294.31# #g*mol^-1#.

However, we are interested in the sample's percentage nitrogen composition:

#(2xx14.011*g*mol^-1)/(294.31*g*mol^-1)# #xx# #100%# #=# #??%#

Keep in mind that the total of each elemental percentage needs to be 100%. Why?

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Answer 2

Aspartame (C14H18N2O5) has a mass percentage composition of roughly 40.91% carbon (C), 4.82% hydrogen (H), 6.36% nitrogen (N), and 47.91% oxygen (O).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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