What is the percent by mass of #NaHCO_3# in a solution containing 20 g #NaHCO_3#, dissolved in 600 mL #H_2O#?

Question

Naomi Aronson · Accepted Answer

#"Approx. 3%"# We simply work out the quotient: #"Mass of sodium bicarbonate"/"Mass of sodium bicarbonate solution"xx100%=# #(20*g)/(20*g+600*g)xx100%=3.2%(m/m)#

Olivia Anton · Answer

undefined To calculate the percent by mass of NaHCO3 in the solution:

1. Calculate the total mass of the solution.
2. Determine the mass of NaHCO3.
3. Use the formula:

$$
\text{Percent by mass of NaHCO}_3 = \frac{\text{Mass of NaHCO}_3}{\text{Total mass of solution}} \times 100\%
$$

Given:
- Mass of NaHCO3 = 20 g
- Volume of H2O = 600 mL

The density of water is approximately 1 g/mL.

1. Total mass of the solution = Mass of NaHCO3 + Mass of water
2. Mass of water = Volume of water × Density of water

Calculate:

- Mass of water = 600 mL × 1 g/mL = 600 g
- Total mass of the solution = 20 g (NaHCO3) + 600 g (water) = 620 g

Using the formula:

$$
\text{Percent by mass of NaHCO}_3 = \frac{20 g}{620 g} \times 100\%
$$

$$
\text{Percent by mass of NaHCO}_3 ≈ 3.23\%
$$