What is the ordered pair solution when x=2 #f(x)=2x^3+x^2-10x-5#?

Answer 1

Avery Alexander

#(2, -5)#

Simply plug in #x=2# into #f(x)=2x^3+x^2-10x-5# to determine the #y-#coordinate.

#f(2)=2(2)^3+2^2-10(2)-5=2(8)+4-20-5#

#f(2)=16+4-20-5=-5#

The ordered pair is then #(2, -5)#

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Answer 2

Ethan Adkins

The ordered pair solution when ( x = 2 ) for the function ( f(x) = 2x^3 + x^2 - 10x - 5 ) is ( (2, -9) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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