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What is the number of moles of beryllium atoms in 36 g of #Be#?

Answer 1

Mateo Aguilar

Approx. #4# #"moles"#. Thus #4xxN_A# beryllium atoms, where #N_A = "Avogadro's number"#

The atomic mass of berylium #=# #9.012*g*mol^-1#.

Thus #"Avogadro's number"# of beryllium atoms has a mass of just over #9# #g#.

Since #N_A = "Avogadro's number"# #=# #6.022xx10^23# #mol^-1#, the number of beryllium atoms #=#

#(36.0*cancelg)/(9.012*cancelg*cancel(mol^-1)# #xx# #6.022xx10^23*cancel(mol^-1)# #=# #??#

AS REQUIRED, the response is a dimensionless number.

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Answer 2

Kai Bowman

The formula to calculate the number of moles of beryllium atoms in 36 g of Be is as follows: number of moles = mass of substance (in grams) / molar mass of substance (in grams per mole). Since the molar mass of beryllium (Be) is about 9.012 grams per mole, number of moles = 36 g / 9.012 g/mol ≈ 3.99 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.