What is the number of moles in 500 L of #He# gas at STP?

Answer 1

#"20 moles"#

The important thing to realize here is that you're working under STP conditions, which implies that you can use the molar volume of a gas at STP to find how many moles of helium will occupy that volume.

Now, the molar volume of a gas represents the volume occupied by one mole of a gas under some specific conditions for pressure and temperature.

Starting from the ideal gas law equation

#color(blue)(PV = nRT)#
you can say that the molar volume of gas at a pressure #P# and a temperature #T# will be equal to
#V/n = (RT)/P#
Now, Standard Temperature and Pressure conditions are defined as a pressure of #"100 kPa"# and a temperature of #0^@"C"#. Under these specific conditions, the molar volume of a gas will be equal to
#V/n = (0.0821 * (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(100/101.325color(red)(cancel(color(black)("atm"))))#
#V/n = "22.7 L/mol"#
This of course implies that one mole of any ideal gas will occupy #"22.7 L"#.
In your case, the volume of the gas is said to be equal to #"500 L"#. This means that you will have
#500 color(red)(cancel(color(black)("L"))) * "1 mole He"/(22.7color(red)(cancel(color(black)("L")))) = "22.026 moles He"#

Rounded to one sig fig, the number of sig figs you have for the volume of the gas, the answer will be

#n_(He) = color(green)("20 moles")#
SIDE NOTE Many textbooks and online sources still list STP conditions as a pressure of #"1 atm"# and a temperature of #0^@"C"#.
Under these conditions for pressure and temperature, one mole of any ideal gas occupies #"22.4 L"#. If these are the values for STP given to you by your instructor, make sure to redo the calculations using #"22.4 L"# instead of #"22.7 L"#.
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Answer 2

At standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters. Therefore, 500 liters of helium gas at STP would contain approximately 22.32 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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