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What is the net ionic equation of #2H^+ + SO_4^(2-) + Ca^(2+) + 2I^- -> CaSO_4 + 2H^+ + 2I^-#?

Answer 1

Wyatt Atkins

Simply cancel out the ions that are COMMON as reactants and products......

#cancel(2H^(+))+SO_4^(2-) + Ca^(2+) + cancel(2I^(-)) rarr CaSO_4(s)darr + cancel(2H^+) + cancel(2I^-)#

to provide.

#Ca^(2+)+SO_4^(2-) rarr CaSO_4(s)darr#

Additionally, you should be asking yourself the following questions:

#"(i) Is mass balanced?"#

#"(ii) Is charge balanced?"#

Well are they? If they are not, then you have not made a reasonable representation of chemical reality. #CaSO_4# is reasonably insoluble in aqueous solution, and it precipitates from solution as a white solid.

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Answer 2

Cameron Andrews

Ca^(2+) + H^+ + SO_4^(2-) -> CaSO_4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the net ionic equation of #2H^+ + SO_4^(2-) + Ca^(2+) + 2I^- -&gt; CaSO_4 + 2H^+ + 2I^-#?

What is the net ionic equation of #2H^+ + SO_4^(2-) + Ca^(2+) + 2I^- -> CaSO_4 + 2H^+ + 2I^-#?