What is the name for the compound with the formula #Sn(CrO_4)_2?#

Answer 1

Stannic chromate or tin(IV) chromate

We're asked to find the name of the compound #"Sn(CrO"_4")"_2#.

This is considered an ionic compound, with the constituent ions being

a tin cation

the chromate anion, #"CrO"_4^(2-)#
This being a compound, the sum of the ionic charges must be #0#.
We know the charge of the chromate ion is #2-#, so we need to find the charge of the #"Sn"# cation, by asking, "What must the charge (oxidation state) of tin be so that the net charge is zero?"

There is one cation per two anions in this compound, so we have

#overbrace((1)(x))^"tin" + overbrace((2)(-2))^("CrO"_4^(2-)) = 0#
#x = color(red)(4#
The oxidation state of tin here is thus #(IV)#, so the name is

Tin(IV) chromate

or

Stannic chromate

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Answer 2

The compound with the formula Sn(CrO₄)₂ is named tin(II) chromate.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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