What is the moment of inertia of a pendulum with a mass of #2 kg# that is #7 m# from the pivot?

Answer 1

The answer is #I = mr^2# = 98 #kgm^2#

Assuming you are not being asked to derive the moment of inertia of the pendulum, I will state without proof that this is

#I = mr^2#
where #m# is the mass hanging from the pendulum and #r# is the distance from the pivot to the centre of the mass.

With your values, this comes to

#I = 2 xx 7^2# = 98 #kgm^2#
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Answer 2

The moment of inertia of the pendulum is 98 J·s².

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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