What is the mole fraction of #NaOH# in an aqueous solution that contains 15.0% #NaOH#?

Answer 1

See Below :)

15% NaOH by mass is 15g of NaOH in (100-15)g of solution.

No. Of moles of NaOH in solution = 0.65

No of moles of Water in solution = 4.72

Mole Fraction = #("(Moles of Solvent)"/"(Moles Of Solute)+(Moles of Solvent)")# OR #("(Moles of Solvent)"/"Total Number Of Moles")#

= 0.65 / 5.37 = 0.121

PS - Calculated this as per 'What is the mole fraction of NaOH in an aqueous solution that contains 15.0% NaOH by mass?'

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Answer 2

Caleb Adams

Mole fraction of NaOH is equal to moles of NaOH / moles of all components in the solution. To find the mole fraction of NaOH, first calculate the moles of water and NaOH separately using their respective molar masses.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.