What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution?

Question

Cameron Andrews · Accepted Answer

#"Molarity"=0.264*mol*L^-1#

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus #"Molarity"=((9.63*g)/(36.46*g*mol^-1))/(1.5*L)=0.264*mol*L^-1.#

Note that our dimensions our consistent. We wanted an answer with units of concentrations, i.e. #mol*L^-1#, and the given quotient gave us an answer with such units. It is all too easy to multiply when you should divide, and vice versa.

What is this solution's pH number?

Peyton Adams · Answer

undefined To find the molarity, you first need to calculate the number of moles of HCl in the solution, using its molar mass (HCl = 1.0079 g/mol for H + 35.453 g/mol for Cl). Then divide the number of moles by the volume of the solution in liters. The molarity (M) is calculated as moles of solute divided by liters of solution.

Molarity (M) = moles of solute / liters of solution

1. Calculate the number of moles of HCl:
   moles = mass / molar mass

2. Convert the volume from liters to milliliters if necessary:
   1.5 L = 1500 mL

3. Calculate the molarity:
   Molarity (M) = moles / volume (in liters)