What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution?

Question

Cameron Andrews · Accepted Answer

The number of moles of dissolved solute per liter of solution is known as the molarity of a solution.

Number of moles of solute / volume of solution (L) equals molarity (M).

Solution Volume: 100 milliliters, or 0.1 liters

moles of Ca#Cl_2# = mass of Ca#Cl_2# / molar mass of Ca#Cl_2#

moles of Ca#Cl_2# = 11g / 111 g#mol^-1# = 0.099 mol

Number of moles of solute / volume of solution (L) equals molarity (M).

Molarity (M) is equal to 0.99 mol/0.1 L (0.099 mol/0.1 L).

Caleb Adams · Answer

undefined To calculate the molarity of the solution, first, determine the number of moles of CaCl2, then divide by the volume of the solution in liters.

1. Calculate the molar mass of CaCl2:
   Ca: 1 × 40.08 g/mol = 40.08 g/mol
   Cl: 2 × 35.45 g/mol = 70.90 g/mol
   Molar mass of CaCl2 = 40.08 g/mol + 70.90 g/mol = 110.98 g/mol

2. Calculate the number of moles of CaCl2:
   Number of moles = Mass / Molar mass
   Number of moles = 11 g / 110.98 g/mol = 0.0992 mol

3. Calculate the volume of the solution in liters:
   100 mL = 100 mL × (1 L / 1000 mL) = 0.1 L

4. Calculate the molarity of the solution:
   Molarity = Number of moles / Volume of solution (in liters)
   Molarity = 0.0992 mol / 0.1 L ≈ 0.992 M

Therefore, the molarity of the solution is approximately 0.992 M.