What is the molarity of a 2.0 L sodium hydroxide solution containing 10.0 grams of solute?

Answer 1

#"Molarity"=0.125*mol*L^-1#

We take the quotient, #((10.0*g)/(40.00*g*mol^-1))/(2.0*L)=0.125*mol*L^-1#.
Note the dimensional consistency of the answer....#1/(mol^-1)=1/(1/(mol))=mol#.
What are the concentrations with respect to #Na^+# and #HO^-# ions?

What is this solution's pH?

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Answer 2

To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters.

First, calculate the number of moles of sodium hydroxide (NaOH) using its molar mass:

Molar mass of NaOH = 22.99 g/mol (Na) + 15.999 g/mol (O) + 1.008 g/mol (H) = 39.997 g/mol

Now, calculate the number of moles of NaOH: Number of moles = Mass of solute / Molar mass Number of moles = 10.0 g / 39.997 g/mol ≈ 0.250 mol

Next, calculate the molarity using the formula: Molarity (M) = Number of moles of solute / Volume of solution (in liters)

Given that the volume of the solution is 2.0 L, substitute the values into the formula: Molarity = 0.250 mol / 2.0 L = 0.125 M

Therefore, the molarity of the sodium hydroxide solution is 0.125 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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