What is the molarity of .50 g of #Na# dissolved in a 1.5 L solution?

Answer 1

In aqueous solution, approx. #0.015*mol*L^-1# with respect to sodium ion.

#Na+H_2O rarr NaOH(aq) + 1/2H_2(g)uarr#
#"Moles of sodium metal"# #=# #(0.50*g)/(22.99*g*mol^-1)#
#"Concentration"# #=# #"Amount in moles"/"Volume of solution (L)"#
#=# #(0.50*g)/(22.99*g*mol^-1)xx1/(1.5*L)#
#=# #??mol*L^-1#.
Under standard conditions (#"298K, 1 atm"#), what volume of gas will be evolved?

It should be noted that I could have dissolved the sodium in mercury metal—in fact, synthetic laboratories frequently do this—but that would have resulted in a fairly heavy solution.

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Answer 2

The molarity of the solution is approximately 1.1 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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