Home > Chemistry > Molarity

What is the molarity of 0.080 moles #NaHCO_3# in 1250 mL of solution?

Answer 1

Caleb Adams

#"Molarity = 0.064"*mol*L^-1#

#"Molarity"# #=# #"Amount of substance (moles)"/"Volume of solution (L)"#

#=# #(0.080*mol)/(1.250*L)# #=# #0.064"*mol*L^-1# with respect to sodium bicarbonate.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Cooper Anderson

Molarity (M) is calculated by dividing the number of moles of solute by the volume of solution in liters.

Given: Moles of NaHCO₃ = 0.080 moles Volume of solution = 1250 mL = 1250/1000 = 1.25 liters

Molarity (M) = Moles of solute / Volume of solution

Molarity = 0.080 moles / 1.25 liters Molarity ≈ 0.064 M

The molarity of the solution is approximately 0.064 M.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.