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What is the molar volume of 46.00 grams of nitrogen gas?

Answer 1

The only way to calculate a substance's molar volume is to supply information about temperature and pressure in molar volume problems.

Starting from the ideal gas law, #PV = nRT#, the expression of an ideal gas' molar volume is

#PV = nRT -> (nRT)/P -> V/n = (RT)/P = V_(molar)#

If we assume STP conditions of 273.15 K and 1.00 atm, one mole of gas will occupy the following volume:

#V/(1 mol e) = (0.082(L * atm)/(mol * K) * 273.15K)/(1.00 atm) = 22.4L/(mol) = V_(molar)#

Consequently, the volume occupied at STP will increase with the number of moles of the gas:

#n_(N_2) = m/(molar.mass) = (46.0g)/(14.0g/(mol)) = 3.29# moles. So,

#V = n * V_(molar) = 3.29 mol es * 22.4L/(1 mol) = 73.7L#

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Answer 2

Xavier Avery

The molar volume of nitrogen gas at standard temperature and pressure (STP) is 22.4 liters per mole. To find the molar volume of 46.00 grams of nitrogen gas, we need to first determine the number of moles of nitrogen gas using its molar mass, which is approximately 28.02 grams per mole. Then, we can use the molar volume to find the volume occupied by that amount of nitrogen gas.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.