What is the molar mass of iron (III) oxide (#Fe_2O_3#)?

Question

Henry Antrim · Accepted Answer

#159.70 g/(mol)#

#color(purple)"We will use the formula below to answer the question:"#

atomic weight of element #xx#number of atoms given by subscript #= molar mass

First, you want to have a periodic table available so you can determine the atomic weight of Fe and O:

From the chemical formula, there are 2 iron atoms, so the atomic mass has to be multiplied by 2, which gives you a value of 111.7 g/mol

Next, you have 3 oxygen atoms, so you would multiply the atomic mass of O by 3 to obtain an atomic weight of 48.00 g/mol

Now you want to add the mass of each atom together to obtain the molar mass of the entire compound:

#color (magenta) ("111.7 g/mol + 48.00 g/mol = 159.70 g/mol")#

Mateo Aguilar · Answer

undefined The molar mass of iron (III) oxide (Fe2O3) is calculated by summing the atomic masses of its constituent atoms. The atomic mass of iron (Fe) is approximately 55.845 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol. So, to find the molar mass of Fe2O3:

(2 * atomic mass of Fe) + (3 * atomic mass of O) = (2 * 55.845 g/mol) + (3 * 16.00 g/mol) = 111.69 g/mol + 48.00 g/mol = 159.69 g/mol

Therefore, the molar mass of iron (III) oxide (Fe2O3) is approximately 159.69 g/mol.