# What is the molar mass of #Fe_2O_3#, #4H_2O#?

To find the molar mass of a substance, we

Multiply the molar mass of each element by however many atoms of that element are in the compound.

Sum the total, and that will be the molar mass of the entire compound

(1)

The molar masses of each element in this compound are

(2)

Now, let's multiply these values by the number of each element in the compound:

(3)

Lastly, to find the molar mass, we simply sum the total of the individual elements/ values:

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The molar mass of Fe2O3•4H2O (iron(III) oxide tetrahydrate) can be calculated by adding the molar masses of the individual elements. The molar mass of Fe is approximately 55.845 g/mol, O is approximately 16.00 g/mol, and H is approximately 1.008 g/mol. Therefore, the molar mass of Fe2O3•4H2O is:

(2 * 55.845 g/mol Fe) + (3 * 16.00 g/mol O) + (4 * 2 * 1.008 g/mol H) = 159.688 g/mol Fe2O3•4H2O

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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