What is the molar mass of a non-electrolyte compound if 4.28 grams is dissolved in 25.0 grams of chloroform solvent to form a solution which has a boiling point elevation of 2.30 degrees celsius?

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In your problem,

You have 4.28 g of compound in 0.0250 kg solvent.

The molar mass is 270 g/mol.

To find the molar mass of the non-electrolyte compound, we can use the formula for boiling point elevation:

ΔT = i * K_b * m

Where: ΔT = Boiling point elevation i = Van't Hoff factor (for non-electrolytes, i = 1) K_b = Ebullioscopic constant (for chloroform, K_b = 3.63 °C/m) m = Molality of the solution

First, we need to calculate the molality of the solution:

Molality (m) = moles of solute / mass of solvent in kg

Given: Mass of solute = 4.28 grams Mass of solvent = 25.0 grams ΔT = 2.30 degrees Celsius K_b = 3.63 °C/m

Moles of solute = mass / molar mass

Molar mass (M) = mass / moles

Then we use the molality formula to find molality (m).

Finally, we plug all values into the boiling point elevation formula to solve for the molar mass (M).

Let's start the calculation.First, let's find the moles of the solute:

Moles of solute = mass / molar mass

Moles of solute = 4.28 grams / molar mass

Next, we calculate the molality of the solution:

Molality (m) = moles of solute / mass of solvent in kg

Mass of solvent in kg = 25.0 grams / 1000 = 0.025 kg

Now, we can calculate the molality:

Molality (m) = (4.28 grams / molar mass) / 0.025 kg

Now, let's use the boiling point elevation formula:

ΔT = i * K_b * m

Given: ΔT = 2.30 degrees Celsius i = 1 K_b = 3.63 °C/m (for chloroform)

Substituting the values:

2.30 = 1 * 3.63 * [(4.28 / molar mass) / 0.025]

Now, let's solve for the molar mass:

molar mass = (4.28 / (2.30 * 0.025 * 3.63)) * 1000

molar mass ≈ 90.03 g/mol

Therefore, the molar mass of the non-electrolyte compound is approximately 90.03 g/mol.