What is the molality of a solution in which 15 g of #I_2# is dissolved in 500.0 g of alcohol?
The molality is
The molality is
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To find the molality of the solution, first, calculate the moles of solute (I2) using its molar mass. Then, divide the moles of solute by the mass of the solvent (alcohol) in kilograms. Finally, express the result in mol/kg.
Molar mass of I2 = 2 × atomic mass of iodine = 2 × 126.90 g/mol = 253.80 g/mol
Number of moles of I2 = Mass of I2 / Molar mass of I2 = 15 g / 253.80 g/mol ≈ 0.0592 mol
Mass of alcohol = 500.0 g = 0.500 kg
Molality (m) = Moles of solute / Mass of solvent (in kg) = 0.0592 mol / 0.500 kg ≈ 0.1184 mol/kg
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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