What is the maximum value of #y=-3sinx+2#?

Answer 1

Scarlett Allison

#5#

For: #y=-3sinx+2#

Since #sinx# is multiplied by a negative value, we want #sinx# to be a minimum value.

#0<=x<=2pi#

#-1<= sinx<=1#

Maximum value:

If #x= (3pi)/2#. then #sinx= -1# and #-3sinx+2=5#

Graph:

graph{-3sinx+2 [-12.66, 12.65, -6.33, 6.33]}

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Answer 2

Ezra Adams

The maximum value of the function y = -3sin(x) + 2 is 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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