What is the mass percent of a solution that contains 45.6 grams ethanol (#C_2H_6O#) in 254 grams of water?

Answer 1

The solution is 15.2% m/m.

The ratio of the mass of the solute—in your case, ethanol—to the mass of the entire solution—which is made up of both ethanol and water—is known as the mass percent of a solution.

This is referred to as the mass-per-concentration percentage, or %m/m.

Thus, the solution's mass will be

#m_"solution" = m_"ethanol" + m_"water"#
#m_"solution" = 45.6 + 254 = "299.6 g"#

This indicates that the solution's mass percentage is

#"%m/m" = m_"solute"/m_"solution" * 100#
#"%m/m" = (45.6cancel("g"))/(299.6cancel("g")) * 100 = color(green)("15.2%")#
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Answer 2

The mass percent of the solution is 15.2%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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